# Juggler sequence Solution

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## Description

Assignment Overview

This assignment will give you experience on the use of loop and conditional statements. We are going work with the [juggler sequence](https://en.wikipedia.org/wiki/Juggler_sequence).

Background

The juggler sequence is another of the well known sequences similar to the Collatz sequence. It has the following definition:

The └ ┘ symbol is the **floor** function, rounding any floating point value **down** to an integer. It is not rounding as you would typically define it. It is essentially truncation of the fractional part, leaving the integer part of the floating point number. It returns a floating point number.

– floor(123.23) is 123.0

– floor(123.999) is 123.0

Some things to note about the juggler sequence:

– Every known starting number eventually ends in the value 1. At that point the sequence ends.

– The numbers can get quite large, so make sure you use the correct type. Even with the correct types you can exceed the size of a long integer.

– The cmath library provides a number of useful methods including pow, sqrt and floor (look them up). Some example sequences are on the Wikipedia page.

Project Description / Specification

Input

**Two integers**

– a low value and a high value (in that order) indicating a range. You are to generate the Juggler sequence for every number in that range and report as follows.

– if the high value is strictly less than the low value, output Error and quit.

Output

If high is greater than or equal to low, on two separate lines you will print:

– the sequence of the longest length. You will print the starting number, a space, and the length.

– the sequence that generated the largest number. You will print the starting number, a space, and the largest number generated.

Notes

– The max value that can be represented by a signed int is ± 2,147,483,647. You need to use a long which has a max of ± 9,223,372,036,854,775,807.

– You need a square root operation for the project. Here you go.

“`c++

include <cmath>  // the head File

cout << sqrt(16) << endl;  // result is 4

“`

1. You should check that the smallest (the first entered value) is indeed strictly smaller than the second (the second value). If not, the program prints the message **Error** (exactly that, capital E Error) and stops.

1. If you ask for a large enough element, you might overflow an integer. If you go big enough, you will overflow a long (though it will take awhile).

1. The **floor** function, when given an argument of a type **double**, returns a **double**. If you want to create a copy of a **double** as a **long**, use `static_cast<long>(the_double)`.

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